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Exercise 13

1. ..clause 1..: Basic knowledge
3. Memo
4. ..clause 4..: Description type
5. ..clause 5..: Basic knowledge(example solution)
6. ..clause 6..: Program readout(example solution)
7. Memo(example solution)
8. ..clause 8..: Description type(example solution)

[1] Basic knowledge

[  1-1  ]
What is called the method of the summary of the variable of the same type handling?
Example solution

It returns to contents.

[  2-1  ]
What does the following program calculate?
Judging from the content of processing and the variable identifier, answer.
```
#include <stdio.h>

int main(void)
{
int data[] = {79,42,39,79,13,75,19};
int i,sum = 0,avg;

for (i = 0;i < sizeof(data) / sizeof(data[0]);i++) { sum += data[i];
}

avg = sum / (sizeof(data) / sizeof(data[0]));

printf("%d\n",avg);

return 0;
}
```
Example solution

It returns to contents.

Memo

[  3-1  ]
Make the program that displays ten input numerical values at the end.
Example solution

It returns to contents.

[4] Description type

[  4-1  ]
Explain concisely what the maximum advantage of the array is.
Example solution

It returns to contents.

[5] Basic knowledge(example solution)

[  1-1  ]
Array
Problem

It returns to contents.

[  2-1  ]
The mean value is calculated.
Problem

It returns to contents.

Memo(example solution)

[  3-1  ]
```
#include <stdio.h>

int main(void)
{
int data[10];
int i;

Turn..numerical value..input.
scanf("%d",&data[i]);
}

for (i = 9;i >= 0;i--) {
printf("%d ",data[i]);
}
printf("\n");

return 0;
}
```
- Though the loop is turned to reverse order when it displays it here
You may reverse only the number displayed in the nether way if it is cramped.
```
for (i = 0;i < 10;i++) { printf("%d ",data
[9 - i]);
}
```
Problem

It returns to contents.

[8] Description type(example solution)

[  4-1  ]
A large amount of variable should be able to be treated collectively by specifying the number by the variable.
Problem

It returns to contents.

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